How do you calculate Hardy-Weinberg?
How do you calculate Hardy-Weinberg?
The Hardy-Weinberg equation used to determine genotype frequencies is: p2 + 2pq + q2 = 1. Where ‘p2’ represents the frequency of the homozygous dominant genotype (AA), ‘2pq’ the frequency of the heterozygous genotype (Aa) and ‘q2’ the frequency of the homozygous recessive genotype (aa).
What does P Q 1 represent?
The Hardy-Weinberg Law is an equation for calculating the frequencies of different alleles and genotypes in a population in genetic equilibrium and expressed by the formula p + q = 1 where p is the frequency of the dominant allele and q is the frequency of the recessive allele.
What is 2pq?
In the equation, p2 represents the frequency of the homozygous genotype AA, q2 represents the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa.
What are the 5 principles of the Hardy Weinberg equilibrium?
There are five basic Hardy-Weinberg assumptions: no mutation, random mating, no gene flow, infinite population size, and no selection.
How do you calculate p and q allele frequencies?
To determine q, which is the frequency of the recessive allele in the population, simply take the square root of q2 which works out to be 0.632 (i.e. 0.632 x 0.632 = 0.4). So, q = 0.63. Since p + q = 1, then p must be 1 – 0.63 = 0.37.
Why is 2pq not PQ?
Note that the heterozygotes are not 2pq but pq because in each case they are only being considered for the one allele in question. If we scale all wii’s such that the largest = 1.0 we refer to these as the relative fitnesses of the genotypes. A worked example where p = . 4, q = .
What does q2 mean in the Hardy Weinberg equation?
p2= dominant allele i.e when we have both ‘p’ from parents. q2= recessive allele i.e when we have bothe ‘q’ from parents. and 2pq= heterozygote i.e. when we have say’p’ from one parent and ‘q’ from another parent.
How do you find the frequency of carriers in Hardy Weinberg?
The carrier frequency can then be calculated as 2X99/100×1/100 which approximates to 1 in 50. Thus a rough approximation of the carrier frequency can be obtained by doubling the square root of the disease incidence. For an X-linked disorder the frequency of affected males equals the frequency of the mutant allele, q.
What are the 5 conditions of the Hardy Weinberg principle?
Five conditions are required in order for a population to remain at Hardy-Weinberg equilibrium: A large breeding population. Random mating. No change in allelic frequency due to mutation. No immigration or emigration. No natural selection.
What is the answer for the Hardy Weinberg equation?
Hardy-Weinberg principle can be illustrated mathematically with the equation: p2+2pq+q2 = 1, where ‘p’ and ‘q’ represent the frequencies of alleles. P added to q always equals one (100%).
What is the Hardy Weinberg formula?
The Hardy Weinberg formula is a principle or law/theorem that states that genotype and allele frequencies in a population will stay the same (or remain constant) for generations.
What is the Hardy Weinberg equation used for?
The Hardy-Weinberg Law is an equation for calculating the frequencies of different alleles and genotypes in a population in genetic equilibrium and expressed by the formula p + q = 1 where p is the frequency of the dominant allele and q is the frequency of the recessive allele.
