How do you find moles of AgNO3?

How do you find moles of AgNO3?

you find moles of AgNO3. That is 0.0132 g AgNO3 x 1 mol AgNO3/169.9 g = 7.77×10-5 moles. Since there is 1 mole Ag and 1 mole NO3 per mole of AgNO3, this is also the number of moles of Ag+ and NO3- ions.

What is the molar mass of silver nitrate AgNO3 in g mol?

169.8 grams per mole
Hence, the molar mass of AgNO3 is 169.8 grams per mole.

What is the molar mass of ag2s?

247.8 g/mol
Silver sulfide/Molar mass

How do you calculate the molar mass of silver?

107.8682 u
Silver/Atomic mass

What is the molar mass of Pb Cr2O7 2?

639.2 g/mol
The molar mass of Pb(Cr2O7)2 is 639.2 g/mol.

What is the N factor of AgNO3?

Equivalent weight = molar wt. / n- factor !!! and n factor for AgNO3 is 1 !!!

What is AgNO3 in the periodic table?

Silver nitrate is an inorganic compound with the chemical formula AgNO3. In its solid form, silver nitrate is coordinated in a trigonal planar arrangement. It is often used as a precursor to other silver-containing compounds.

What is the molar mass of fe2s3?

207.9 g/mol
Iron(III) sulfide/Molar mass

What is the molar mass of nh4 2so4?

132.14 g/mol
Ammonium sulfate/Molar mass

How many grams are there in 2.3 moles of silver?

Use dimensional analysis to convert the number of atoms to moles. Convert the moles of Ag to mass. The mass of 2.3 × 10²⁴ Ag atoms is approximately 410 g.

What is the formula for AgNO3?

The formula of the chemical compound Silver nitrate is AgNO3

What is the atomic weight of AgNO3?

The molar mass of silver nitrate (AgNO3) is found by adding up the weight of its parts. The molecular weight of silver is 107.87, nitrogen is 14, and oxygen is 16. The sum of 107.87 + 14 + 48 (3 oxygens) equals 169.87 grams per mole.

What is the molar mass of 2agno3?

Formula: 2AgNO3. Molar Mass: 171.872 g/mol 1g=5.81828337367343E-03 mol. Percent composition (by mass): Element count Atom Mass %(by mass) Ag 1 107.868 63.92%.

How do you calculate molar mass?

The best way to calculate molar mass of a compound is by counting the number of atoms of a type present in it and by multiplying the number with the molecular mass of that atom . Just do the same for the other atoms present in the compound .

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